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AHSME 1979 Problem 12

    In the adjoining figure, CDCD is the diameter of a semi-circle with center OO. Point AA lies on the extension of DCDC past CC; point EE lies on the semi-circle, and BB is the point of intersection (distinct from EE ) of line segment AEAE with the semi-circle. If length ABAB equals length ODOD, and the measure of ∡EOD\measuredangle EOD is 45∘45^\circ, then the measure of ∡BAO\measuredangle BAO is (A) 10∘(B) 15∘(C) 20∘(D) 25∘(E) 30∘\textbf{(A) }10^\circ \textbf{(B) }15^\circ \textbf{(C) }20^\circ \textbf{(D) }25^\circ \textbf{(E) }30^\circ

    Dataset text NuminaMath-1.5. Quoted with source.

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