Home Competitions AHSME 1979 Problem 11
Find a positive integral solution to the equation
1 + 3 + 5 + ⋯ + ( 2 n − 1 ) 2 + 4 + 6 + ⋯ + 2 n = 115 116 \frac{1+3+5+\dots+(2n-1)}{2+4+6+\dots+2n}=\frac{115}{116} 2 + 4 + 6 + ⋯ + 2 n 1 + 3 + 5 + ⋯ + ( 2 n − 1 ) = 116 115 (A) 110 (B) 115 (C) 116 (D) 231 (E) The equation has no positive integral solutions. \textbf{(A) }110 \textbf{(B) }115 \textbf{(C) }116 \textbf{(D) }231 \\ \textbf{(E) }\text{The equation has no positive integral solutions.} (A) 110 (B) 115 (C) 116 (D) 231 (E) The equation has no positive integral solutions.
Dataset text NuminaMath-1.5 . Quoted with source.
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