Home Competitions AHSME 1974 Problem 5
Given a quadrilateral A B C D ABCD A B C D A B AB A B B B B E E E ∡ B A D = 92 ∘ \measuredangle BAD=92^\circ ∡ B A D = 9 2 ∘ ∡ A D C = 68 ∘ \measuredangle ADC=68^\circ ∡ A D C = 6 8 ∘ ∡ E B C \measuredangle EBC ∡ E B C ( A ) 66 ∘ ( B ) 68 ∘ ( C ) 70 ∘ ( D ) 88 ∘ ( E ) 92 ∘ \mathrm{(A)\ } 66^\circ \mathrm{(B) \ }68^\circ \mathrm{(C) \ } 70^\circ \mathrm{(D) \ } 88^\circ \mathrm{(E) \ }92^\circ ( A ) 6 6 ∘ ( B ) 6 8 ∘ ( C ) 7 0 ∘ ( D ) 8 8 ∘ ( E ) 9 2 ∘
Dataset text NuminaMath-1.5 . Quoted with source.
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