Construct outside the acute-angled triangle ABC the isosceles triangles ABAB,ABBA, ACAC,ACCA,BCBC and BCCB, so that
AB=ABA=BAB,AC=ACA=CAC,BC=BCB=CBC
and
∡BABA=∡ABAB=∡CACA=∡ACAC=∡BCBC=∡CBCB=α<90∘.
Prove that the perpendiculars from A to BACA, from B to ABCB and from C to ACBC are concurrent.