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BALKAN-SL 2017 G6

    Construct outside the acute-angled triangle ABCA B C the isosceles triangles ABAB,ABBAA B A_{B}, A B B_{A}, ACAC,ACCA,BCBCA C A_{C}, A C C_{A}, B C B_{C} and BCCBB C C_{B}, so that

    AB=ABA=BAB,AC=ACA=CAC,BC=BCB=CBCA B=A B_{A}=B A_{B}, A C=A C_{A}=C A_{C}, B C=B C_{B}=C B_{C}

    and

    ∡BABA=∡ABAB=∡CACA=∡ACAC=∡BCBC=∡CBCB=α<90∘.\measuredangle B A B_{A}=\measuredangle A B A_{B}=\measuredangle C A C_{A}=\measuredangle A C A_{C}=\measuredangle B C B_{C}=\measuredangle C B C_{B}=\alpha<90^{\circ} .

    Prove that the perpendiculars from AA to BACAB_{A} C_{A}, from BB to ABCBA_{B} C_{B} and from CC to ACBCA_{C} B_{C} are concurrent.

    Dataset text NuminaMath olympiads. Quoted with source.

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