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AHSME 1970 Problem 10

    Let F=.48181⋯F=.48181\cdots be an infinite repeating decimal with the digits 88 and 11 repeating. When FF is written as a fraction in lowest terms, the denominator exceeds the numerator by (A) 13(B) 14(C) 29(D) 57(E) 126\text{(A) } 13 \text{(B) } 14 \text{(C) } 29 \text{(D) } 57 \text{(E) } 126

    Dataset text NuminaMath-1.5. Quoted with source.

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