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US-TST 2002 Problem 2

    Let p>5p>5 be a prime number. For any integer xx , define fp(x)=∑k=1p−11(px+k)2{f_p}(x) = \sum_{k=1}^{p-1} \frac{1}{(px+k)^2} Prove that for any pair of positive integers xx , yy , the numerator of fp(x)−fp(y)f_p(x) - f_p(y) , when written as a fraction in lowest terms, is divisible by p3p^3 .

    Dataset text AI-MO AoPS. Quoted with source.

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