AHSME 1969 Problem 25

If it is known that $\log_2(a)+\log_2(b) \ge 6$, then the least value that can be taken on by $a+b$ is: $\text{(A) } 2\sqrt{6} \text{(B) } 6 \text{(C) } 8\sqrt{2} \text{(D) } 16 \text{(E) none of these}$