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AHSME 1969 Problem 17

    The equation 22x−8⋅2x+12=02^{2x}-8\cdot 2^x+12=0 is satisfied by: (A) log(3)(B) 12log(6)(C) 1+log(32)(D) 1+log(3)log(2)(E) none of these\text{(A) } log(3) \text{(B) } \tfrac{1}{2}log(6) \text{(C) } 1+log(\tfrac{3}{2}) \text{(D) } 1+\frac{log(3)}{log(2)} \text{(E) none of these}

    Dataset text NuminaMath-1.5. Quoted with source.

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