AHSME 1968 Problem 8

A positive number is mistakenly divided by $6$ instead of being multiplied by $6.$ Based on the correct answer, the error thus committed, to the nearest percent, is : $\text{(A) } 100 \text{(B) } 97 \text{(C) } 83 \text{(D) } 17 \text{(E) } 3$