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AHSME 1967 Problem 33

    In this diagram semi-circles are constructed on diameters AB‾\overline{AB}, AC‾\overline{AC}, and CB‾\overline{CB}, so that they are mutually tangent. If CD‾⊥AB‾\overline{CD} \bot \overline{AB}, then the ratio of the shaded area to the area of a circle with CD‾\overline{CD} as radius is: (A) 1:2(B) 1:3(C) 3:7(D) 1:4(E) 2:6\textbf{(A)}\ 1:2 \textbf{(B)}\ 1:3 \textbf{(C)}\ \sqrt{3}:7 \textbf{(D)}\ 1:4 \textbf{(E)}\ \sqrt{2}:6

    Dataset text NuminaMath-1.5. Quoted with source.

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