AHSME 1967 Problem 23

If $x$ is real and positive and grows beyond all bounds, then $\log_3{(6x-5)}-\log_3{(2x+1)}$ approaches: $\textbf{(A)}\ 0 \textbf{(B)}\ 1 \textbf{(C)}\ 3 \textbf{(D)}\ 4 \textbf{(E)}\ \text{no finite number}$