olymmath

AHSME 1952 Problem 18

    log⁡p+log⁡q=log⁡(p+q)\log p+\log q=\log(p+q) only if: (A)  p=q=zero(B)  p=q21−q(C)  p=q=1\textbf{(A) \ }p=q=\text{zero} \textbf{(B) \ }p=\frac{q^2}{1-q} \textbf{(C) \ }p=q=1 (D)  p=qq−1(E)  p=qq+1\textbf{(D) \ }p=\frac{q}{q-1} \textbf{(E) \ }p=\frac{q}{q+1}

    Dataset text NuminaMath-1.5. Quoted with source.

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