If xk+1=xk+21 for k=1,2,…,n−1 and x1=1, find x1+x2+⋯+xn.
(A) 2n+1(B) 2n+3(C) 2n2−1(D) 4n2+n(E) 4n2+3n
Dataset text NuminaMath-1.5. Quoted with source.
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