AHSME 1961 Problem 6

When simplified, $\log{8} \div \log{\frac{1}{8}}$ becomes: $\textbf{(A)}\ 6\log{2} \textbf{(B)}\ \log{2} \textbf{(C)}\ 1 \textbf{(D)}\ 0 \textbf{(E)}\ -1$