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AHSME 1961 Problem 1

    When simplified, (−1125)−2/3(-\frac{1}{125})^{-2/3} becomes: (A) 125(B) −125(C) 25(D) −25(E) 25−1\textbf{(A)}\ \frac{1}{25} \textbf{(B)}\ -\frac{1}{25} \textbf{(C)}\ 25 \textbf{(D)}\ -25 \textbf{(E)}\ 25\sqrt{-1}

    Dataset text NuminaMath-1.5. Quoted with source.

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    25

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