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AMC 10 2015a Problem 1

  • Paper

What is the value of (20−1+52+0)−1×5(2^0-1+5^2+0)^{-1}\times 5 ? (A) −125(B) −120(C) 15(D) 524(E) 25\textbf{(A) }-125 \textbf{(B) }-120 \textbf{(C) }\dfrac15 \textbf{(D) }\dfrac5{24} \textbf{(E) }25

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