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AHSME 1960 Problem 23

    The radius RR of a cylindrical box is 88 inches, the height HH is 33 inches. The volume V=πR2HV = \pi R^2H is to be increased by the same fixed positive amount when RR is increased by xx inches as when HH is increased by xx inches. This condition is satisfied by: (A) no real value of x(B) one integral value of x(C) one rational, but not integral, value of x(D) one irrational value of x(E) two real values of x\textbf{(A)}\ \text{no real value of x} \\ \textbf{(B)}\ \text{one integral value of x} \\ \textbf{(C)}\ \text{one rational, but not integral, value of x} \\ \textbf{(D)}\ \text{one irrational value of x} \\ \textbf{(E)}\ \text{two real values of x}

    Dataset text NuminaMath-1.5. Quoted with source.

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    \frac{16}{3}

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