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AHSME 1950 Problem 35

    In triangle ABCABC, AC=24AC=24 inches, BC=10BC=10 inches, AB=26AB=26 inches. The radius of the inscribed circle is: (A) 26 in(B) 4 in(C) 13 in(D) 8 in(E) None of these\textbf{(A)}\ 26\text{ in} \textbf{(B)}\ 4\text{ in} \textbf{(C)}\ 13\text{ in} \textbf{(D)}\ 8\text{ in} \textbf{(E)}\ \text{None of these}

    Dataset text NuminaMath-1.5. Quoted with source.

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