Home Competitions AHSME 1951 Problem 45
If you are given log 8 ≈ .9031 \log 8\approx .9031 log 8 ≈ .9031 and log 9 ≈ .9542 \log 9\approx .9542 log 9 ≈ .9542 , then the only logarithm that cannot be found without the use of tables is:
(A) log 17 (B) log 5 4 (C) log 15 (D) log 600 (E) log .4 \textbf{(A)}\ \log 17 \textbf{(B)}\ \log\frac{5}{4} \textbf{(C)}\ \log 15 \textbf{(D)}\ \log 600 \textbf{(E)}\ \log .4 (A) log 17 (B) log 4 5 (C) log 15 (D) log 600 (E) log .4
Dataset text NuminaMath-1.5 . Quoted with source.
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