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AHSME 1950 Problem 46

    In triangle ABCABC, AB=12AB=12, AC=7AC=7, and BC=10BC=10. If sides ABAB and ACAC are doubled while BCBC remains the same, then: (A) The area is doubled(B) The altitude is doubled(C) The area is four times the original area(D) The median is unchanged(E) The area of the triangle is 0\textbf{(A)}\ \text{The area is doubled} \\ \textbf{(B)}\ \text{The altitude is doubled} \\ \textbf{(C)}\ \text{The area is four times the original area} \\ \textbf{(D)}\ \text{The median is unchanged} \\ \textbf{(E)}\ \text{The area of the triangle is 0}

    Dataset text NuminaMath-1.5. Quoted with source.

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