Home Competitions AHSME 1950 Problem 46
In triangle A B C ABC A B C , A B = 12 AB=12 A B = 12 , A C = 7 AC=7 A C = 7 , and B C = 10 BC=10 B C = 10 . If sides A B AB A B and A C AC A C are doubled while B C BC B C remains the same, then:
(A) The area is doubled (B) The altitude is doubled (C) The area is four times the original area (D) The median is unchanged (E) The area of the triangle is 0 \textbf{(A)}\ \text{The area is doubled} \\ \textbf{(B)}\ \text{The altitude is doubled} \\ \textbf{(C)}\ \text{The area is four times the original area} \\ \textbf{(D)}\ \text{The median is unchanged} \\ \textbf{(E)}\ \text{The area of the triangle is 0} (A) The area is doubled (B) The altitude is doubled (C) The area is four times the original area (D) The median is unchanged (E) The area of the triangle is 0
Dataset text NuminaMath-1.5 . Quoted with source.
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