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IZhO 2024 Problem 2

    Circles Ω\Omega and Γ\Gamma meet at points AA and BB. The line containing their centres intersects Ω\Omega and Γ\Gamma at points PP and QQ, respectively, such that these points lie on the same side of the line ABAB and point QQ is closer to ABAB than point PP. The circle δ\delta lies on the same side of the line ABAB as PP and QQ, touches the segment ABAB at point DD and touches Γ\Gamma at point TT. The line PDPD meets δ\delta and Ω\Omega again at points KK and LL, respectively. Prove that ∠QTK=∠DTL\angle QTK = \angle DTL.

    Official text International Zhautykov Olympiad 2024 official paper, page 1. Quoted with source.

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