olymmath

VTRMC 2014

Virginia Tech Regional Mathematics Contest 2014.

Other problems

Problem 2

Evaluate ∫02x(16−x2)16−x2+(4−x)(4+x)(12+x2)dx\int^2_0\frac{x(16-x^2)}{16-x^2+\sqrt{(4-x)(4+x)(12+x^2)}}dx .

Problem 3

Find the least positive integer nn such that 220142^{2014} divides 19n−119^n-1 .

Problem 4

Suppose we are given a 19×1919\times19 chessboard (a table with 19219^2 squares) and remove the central square. Is it possible to tile the remaining 192−1=36019^2-1=360 squares with 4×14\times1 and 1×41\times4 rectangles? (So that each of the 360360 squares is covered by exactly one rectangle.) Justify your answer.

Problem 5

Let n≥1n\ge1 and r≥2r\ge2 be positive integers. Prove that there is no integer mm such that n(n+1)(n+2)=mrn(n+1)(n+2)=m^r .

Problem 6

Let SS denote the set of 22 by 22 matrices with integer entries and determinant 11 , and let TT denote those matrices of SS which are congruent to the identity matrix I(mod3)I\pmod3 (so (abcd)∈T\begin{pmatrix}a&bc&d\end{pmatrix}\in T means that a,b,c,d∈Z,ad−bc=1,a,b,c,d\in\mathbb Z,ad-bc=1, and 33 divides b,c,a−1,d−1b,c,a-1,d-1 ).

(a) Let f:T→Rf:T\to\mathbb R be a function such that for every X,Y∈TX,Y\in T with Y≠IY\ne I , either f(XY)>f(X)f(XY)>f(X) or f(XY−1)>f(X)f(XY^{-1})>f(X) . Show that given two finite nonempty subsets A,BA,B of TT , there are matrices a∈Aa\in A and b∈Bb\in B such that if a′∈Aa'\in A , b′∈Bb'\in B and a′b′=aba'b'=ab , then a′=aa'=a and b′=bb'=b . (b) Show that there is no f:S→Rf:S\to\mathbb R such that for every X,Y∈SX,Y\in S with Y≠±IY\ne\pm I , either f(XY)>f(X)f(XY)>f(X) or f(XY−1)>f(X)f(XY^{-1})>f(X) .

Problem 7

Let A,BA,B be two points in the plane with integer coordinates A=(x1,y1)A=(x_1,y_1) and B=(x2,y2)B=(x_2,y_2) . (Thus xi,yi∈Zx_i,y_i\in\mathbb Z , for i=1,2i=1,2 .) A path π:A→B\pi:A\to B is a sequence of down and right steps, where each step has an integer length, and the initial step starts from AA , the last step ending at BB . In the figure below, we indicated a path from A1=(4,9)A_1=(4,9) to B1=(10,3)B1=(10,3) . The distance d(A,B)d(A,B) between AA and BB is the number of such paths. For example, the distance between A=(0,2)A=(0,2) and B=(2,0)B=(2,0) equals 66 . Consider now two pairs of points in the plane Ai=(xi,yi)A_i=(x_i,y_i) and Bi=(ui,zi)B_i=(u_i,z_i) for i=1,2i=1,2 , with integer coordinates, and in the configuration shown in the picture (but with arbitrary coordinates): x2<x1x_2<x_1 and y1>y2y_1>y_2 , which means that A1A_1 is North-East of A2A_2 ; u2<u1u_2<u_1 and z1>z2z_1>z_2 , which means that B1B_1 is North-East of B2B_2 . Each of the points AiA_i is North-West of the points BjB_j , for 1≤i1\le i , j≤2j\le2 . In terms of inequalities, this means that xi<min⁡{u1,u2}x_i<\min\{u_1,u_2\} and yi>max⁡{z1,z2}y_i>\max\{z_1,z_2\} for i=1,2i=1,2 .

Image

(a) Find the distance between two points AA and BB as before, as a function of the coordinates of AA and BB . Assume that AA is North-West of BB . (b) Consider the 2×22\times2 matrix M=(d(A1,B1)d(A1,B2)d(A2,B1)d(A2,B2))M=\begin{pmatrix}d(A_1,B_1)&d(A_1,B_2)d(A_2,B_1)&d(A_2,B_2)\end{pmatrix} . Prove that for any configuration of points A1,A2,B1,B2A_1,A_2,B_1,B_2 as described before, det⁡M>0\det M>0 .