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VMO 2013 Problem 3

    Let ABCABC be a triangle such that ABCABC isn't a isosceles triangle. (I)(I) is incircle of triangle touches BC,CA,ABBC,CA,AB at D,E,FD,E,F respectively. The line through EE perpendicular to BIBI cuts (I)(I) again at KK . The line through FF perpendicular to CICI cuts (I)(I) again at LL . JJ is midpoint of KLKL .a) Prove that D,I,JD,I,J collinear.b) B,CB,C are fixed points, AA is moved point such that ABAC=k\frac{AB}{AC}=k with kk is constant. IE,IFIE,IF cut (I)(I) again at M,NM,N respectively. MNMN cuts IB,ICIB,IC at P,QP,Q respectively. Prove that bisector perpendicular of PQPQ through a fixed point.

    Dataset text AI-MO AoPS. Quoted with source.

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