olymmath

VMO 2012 Problem 6

    Consider two odd natural numbers aa and bb where aa is a divisor of b2+2b^2+2 and bb is a divisor of a2+2.a^2+2. Prove that aa and bb are the terms of the series of natural numbers ⟨vn⟩\langle v_n\rangle defined by v1=v2=1;vn=4vn−1−vn−2  for n≥3.v_1 = v_2 = 1; v_n = 4v_ {n-1}-v_{n-2} \ \ \text{for} \ n\geq 3.

    Dataset text AI-MO AoPS. Quoted with source.

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