VMO 2001 Problem 4
Find the maximum value of 1/√x + 2/√y + 3/√z, where x, y, z are positive reals satisfying 1/√2 ≤ z ≤ min(x√2, y√3), x + z√3 ≥ √6, y√3 + z√10 ≥= 2√5.
Community text Kalva (prase.cz mirror). Quoted with source.
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