olymmath

VMO 1998 Problem 3

    The sequence a0a_0, a1a_1, a2a_2, ... is defined by a0a_0= 20, a1a_1 = 100, an+2a_{n+2} = 4an+14a_{n+1} + 5an5a_n + 20. Find the smallest m such that ama_m - a0a_0, am+1a_{m+1} - a1a_1, am+2a_{m+2} - a2a_2, ... are all divisible by 1998.

    Community text Kalva (prase.cz mirror). Quoted with source.

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