VN-TST 1998 Problem 6
- Day 2
In a conference there are people. It is known that:
I. Each person knows at least other people. II. For each pair of person and who don't know each other, there exist some people such that knows , knows and knows . III. There doesn't exist a Hamilton path.
Prove that: We can divide those people into 2 groups: group has a Hamilton cycle, and the other contains of people who don't know each other.
Dataset text AI-MO AoPS. Quoted with source.
Solutions
No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.
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