olymmath

VN-TST 1993

Vietnam Team Selection Test 1993.

Day 1

Problem 1

  • Day 1

We call a rectangle of size 2×32 \times 3 (or 3×23 \times 2 ) without one cell in corner a PP -rectangle. We call a rectangle of size 2×32 \times 3 (or 3×23 \times 2 ) without two cells in opposite (under center of rectangle) corners a SS -rectangle. Using some squares of size 2×22 \times 2 , some PP -rectangles and some SS -rectangles, one form one rectangle of size 1993×20001993 \times 2000 (figures don't overlap each other). Let ss denote the sum of numbers of squares and SS -rectangles used in such tiling. Find the maximal value of ss .

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Problem 2

  • Day 1

A sequence {an}\{a_n\} is defined by: a1=1,an+1=an+1ana_1 = 1, a_{n+1} = a_n + \dfrac{1}{\sqrt{a_n}} for n=1,2,3,…n = 1, 2, 3, \ldots . Find all real numbers qq such that the sequence {un}\{u_n\} defined by un=anqu_n = a_n^q , n=1,2,3,…n = 1, 2, 3, \ldots has nonzero finite limit when nn goes to infinity.

THERE MIGHT BE A TYPO!

Answer, solutions and source

Problem 3

  • Day 1

Let's consider the real numbers x1,x2,x3,x4x_1, x_2, x_3, x_4 satisfying the condition

12≤x12+x22+x32+x42≤1\dfrac{1}{2}\le x_1^2+x_2^2+x_3^2+x_4^2\le 1

Find the maximal and the minimal values of expression:

A=(x1−2⋅x2+x3)2+(x2−2⋅x3+x4)2+(x2−2⋅x1)2+(x3−2⋅x4)2A = (x_1 - 2 \cdot x_2 + x_3)^2 + (x_2 - 2 \cdot x_3 + x_4)^2 + (x_2 - 2 \cdot x_1)^2 + (x_3 - 2 \cdot x_4)^2

Answer, solutions and source

Day 2

Problem 4

  • Day 2

Let HH , II , OO be the orthocenter, incenter and circumcenter of a triangle. Show that 2⋅IO≥IH2 \cdot IO \geq IH . When does the equality hold ?

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Problem 5

  • Day 2

Let an integer k>1k > 1 be given. For each integer n>1n > 1 , we put

f(n)=k⋅n⋅(1−1p1)⋅(1−1p2)⋯(1−1pr)f(n) = k \cdot n \cdot \left(1-\frac{1}{p_1}\right) \cdot \left(1-\frac{1}{p_2}\right) \cdots \left(1-\frac{1}{p_r}\right)

where p1,p2,…,prp_1, p_2, \ldots, p_r are all distinct prime divisors of nn . Find all values kk for which the sequence {xm}\{x_m\} defined by x0=ax_0 = a and xm+1=f(xm),m=0,1,2,3,…x_{m+1} = f(x_m), m = 0, 1, 2, 3, \ldots is bounded for all integers a>1a > 1 .

Answer, solutions and source

Problem 6

  • Day 2

Let nn points A1,A2,…,AnA_1, A_2, \ldots, A_n , ( n>2n>2 ), be considered in the space, where no four points are coplanar. Each pair of points Ai,AjA_i, A_j are connected by an edge. Find the maximal value of nn for which we can paint all edges by two colors - blue and red such that the following three conditions hold:

I. Each edge is painted by exactly one color. II. For i=1,2,…,ni = 1, 2, \ldots, n , the number of blue edges with one end AiA_i does not exceed 4. III. For every red edge AiAjA_iA_j , we can find at least one point AkA_k ( k≠i,jk \neq i, j ) such that the edges AiAkA_iA_k and AjAkA_jA_k are blue.

Answer, solutions and source