olymmath

UZ-MO 2004

Uzbekistan national mathematics olympiad 2004.

Other problems

Problem 3

Given a sequence { ana_n } such that a1=2a_1=2 and for all positive integer n≥2n\geq 2 an+1=an4+916ana_{n+1}=\frac{a_n^4+9}{16a_n} . Prove that 45<an<54\frac {4}{5}<a_n<\frac {5}{4}