olymmath

USAMO 2024 Problem 5

  • Day 2

Point DD is selected inside acute △ABC\triangle ABC so that ∠DAC=∠ACB\angle DAC = \angle ACB and ∠BDC=90∘+∠BAC\angle BDC = 90^{\circ} + \angle BAC . Point EE is chosen on ray BDBD so that AE=ECAE = EC . Let MM be the midpoint of BCBC .

Show that line ABAB is tangent to the circumcircle of triangle BEMBEM .

Proposed by Anton Trygub

Dataset text AI-MO AoPS. Quoted with source.

Also USAJMO 2024 Problem 6.

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