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US-TST 2018 Problem 4

    Let nn be a positive integer and let S⊆{0,1}nS \subseteq\{0,1\}^{n} be a set of binary strings of length nn. Given an odd number x1,…,x2k+1∈Sx_{1}, \ldots, x_{2 k+1} \in S of binary strings (not necessarily distinct), their majority is defined as the binary string y∈{0,1}ny \in\{0,1\}^{n} for which the ith i^{\text {th }} bit of yy is the most common bit among the ith i^{\text {th }} bits of x1,…,x2k+1x_{1}, \ldots, x_{2 k+1}. (For example, if n=4n=4 the majority of 0000,0000,1101,1100,01010000,0000,1101,1100,0101 is 0100 .) Suppose that for some positive integer k,Sk, S has the property PkP_{k} that the majority of any 2k+12 k+1 binary strings in SS (possibly with repetition) is also in SS. Prove that SS has the same property PkP_{k} for all positive integers kk.

    Dataset text NuminaMath olympiads. Quoted with source.

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