olymmath

US-EGMO-TST 2019 Problem 3

    Let nn be a positive integer such that the number 1k+2k+⋯+nkn\frac{1^k + 2^k + \dots + n^k}{n} is an integer for any k∈{1,2,…,99}k \in \{1, 2, \dots, 99\} . Prove that nn has no divisors between 2 and 100, inclusive.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator us-egmo-tst/2019/p3 · Tag KD9RSKMQD2 · Edit this page on GitHub · Keys: j next, k previous