olymmath

UA-UMO 2023 Problem 116

    Let KK be the midpoint of the median AMAM of a triangle ABCABC . Points X,YX, Y lie on AB,ACAB, AC , respectively, such that ∠KXM=∠ACB\angle KXM =\angle ACB , AX>BXAX>BX and similarly ∠KYM=∠ABC\angle KYM =\angle ABC , AY>CYAY>CY . Prove that B,C,X,YB, C, X, Y are concyclic.

    Proposed by Mykhailo Shtandenko

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ua-umo/2023/p116 · Tag T8V6DJ3D4Z · Edit this page on GitHub · Keys: j next, k previous