olymmath

UA-UMO 1998 Problem 118

  • Grade 11

The sequence (xn)(x_n) is given by x1=1x_1=1 and xn+1=n2xn+xnn2+2for n≥1.x_{n+1}=\frac{n^2}{x_n}+\frac{x_n}{n^2}+2\enspace\text{for }n\ge1. (a) Prove that xn+1≥xnx_{n+1}\ge x_n for all n≥4n\ge4 . (b) Prove that ⌊xn⌋=n\lfloor x_n\rfloor=n for all n≥4n\ge4 .

Dataset text AI-MO AoPS. Quoted with source.

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