olymmath

TUYMAADA 2023 J3

  • Junior

Point LL inside triangle ABCABC is such that CL=ABCL = AB and ∠BAC+∠BLC=180∘\angle BAC + \angle BLC = 180^{\circ} . Point KK on the side ACAC is such that KL∥BCKL \parallel BC . Prove that AB=BKAB = BK

Dataset text AI-MO AoPS. Quoted with source.

Official text: Tuymaada Olympiad 2023 official paper, page 1.

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