olymmath

TUYMAADA 2021 S1

    Polynomials FF and GG satisfy: F(F(x))>G(F(x))>G(G(x))F(F(x))>G(F(x))>G(G(x)) for all real xx .Prove that F(x)>G(x)F(x)>G(x) for all real xx .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tuymaada/2021/s1 · Tag A861YJJGR2 · Edit this page on GitHub · Keys: j next, k previous