TUYMAADA 2020 J6

$AK$ and $BL$ are altitudes of an acute triangle $ABC$ . Point $P$ is chosen on the segment $AK$ so that $LK=LP$ . The parallel to $BC$ through $P$ meets the parallel to $PL$ through $B$ at point $Q$ . Prove that $\angle AQB = \angle ACB$ .

(S. Berlov)