olymmath

TSTST 2022 Problem 4

    A function f:N→Nf: \mathbb{N} \rightarrow \mathbb{N} has the property that for all positive integers mm and nn, exactly one of the f(n)f(n) numbers f(m+1),f(m+2),…,f(m+f(n))f(m+1), f(m+2), \ldots, f(m+f(n)) is divisible by nn. Prove that f(n)=nf(n)=n for infinitely many positive integers nn.

    Dataset text NuminaMath olympiads. Quoted with source.

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