olymmath

TR-MO 2019

Turkish Mathematical Olympiad 2019.

Other problems

Problem 1

a,b,ca, b, c are positive real numbers such that (ab−1)(bc−1)(ca−1)=1(\sqrt {ab}-1)(\sqrt {bc}-1)(\sqrt {ca}-1)=1 At most, how many of the numbers: a−bc,a−cb,b−ac,b−ca,c−ab,c−baa-\frac {b}{c}, a-\frac {c}{b}, b-\frac {a}{c}, b-\frac {c}{a}, c-\frac {a}{b}, c-\frac {b}{a} can be bigger than 11 ?

Problem 2

Let d(n)d(n) denote the number of divisors of a positive integer nn . If kk is a given odd number, prove that there exist an increasing arithmetic progression in positive integers (a1,a2,…a2019)(a_1,a_2,\ldots a_{2019}) such that gcd(k,d(a1)d(a2)…d(a2019))=1gcd(k,d(a_1)d(a_2)\ldots d(a_{2019})) =1

Problem 3

There are 2019 students in a school, and some of these students are members of different student clubs. Each student club has an advisory board consisting of 12 students who are members of that particular club. An {\em advisory meeting} (for a particular club) can be realized only when each participant is a member of that club, and moreover, each of the 12 students forming the advisory board are present among the participants. It is known that each subset of at least 12 students in this school can realize an advisory meeting for exactly one student club. Determine all possible numbers of different student clubs with exactly 27 members.

Problem 4

In a triangle ΔABC\Delta ABC , ∣AB∣=∣AC∣|AB|=|AC| . Let MM be on the minor arc ACAC of the circumcircle of ΔABC\Delta ABC different than AA and CC . Let BMBM and ACAC meet at EE and the bisector of ∠BMC\angle BMC and BCBC meet at FF such that ∠AFB=∠CFE\angle AFB=\angle CFE . Prove that the triangle ΔABC\Delta ABC is equilateral.

Problem 5

Let f:{1,2,…,2019}→{−1,1}f:\{1,2,\dots,2019\}\to\{-1,1\} be a function, such that for every k∈{1,2,…,2019}k\in\{1,2,\dots,2019\} , there exists an ℓ∈{1,2,…,2019}\ell\in\{1,2,\dots,2019\} such that ∑i∈Z:(ℓ−i)(i−k)⩾0f(i)⩽0.\sum_{i\in\mathbb{Z}:(\ell-i)(i-k)\geqslant 0} f(i)\leqslant 0. Determine the maximum possible value of ∑i∈Z:1⩽i⩽2019f(i).\sum_{i\in\mathbb{Z}:1\leqslant i\leqslant 2019} f(i).

Problem 6

Given an integer n>2n>2 and an integer aa , if there exists an integer dd such that n∣ad−1n\mid a^d-1 and n∤ad−1+⋯+1n\nmid a^{d-1}+\cdots+1 , we say aa is n−n- separating. Given any n>2, let the defect of nn be defined as the number of integers aa such that 0<a<n0<a<n , (a,n)=1(a,n)=1 , and aa is not n−n- separating. Determine all integers n>2n>2 whose defect is equal to the smallest possible value.