olymmath

TR-MO 1997 Problem 3

    Let nn and kk be positive integers, where n>1n > 1 is odd. Suppose nn voters are to elect one of the kk cadidates from a set AA according to the rule of "majoritarian compromise" described below. After each voter ranks the candidates in a column according to his/her preferences, these columns are concatenated to form a kk x nn voting matrix. We denote the number of ccurences of a∈Aa \in A in the ii - th row of the voting matrix by aia_{i}. Let lal_{a} stand for the minimum integer ll for which ∑i=1lai>n2\sum^{l}_{i=1}{a_{i}}> \frac{n}{2}. Setting l′=min{la∣a∈A}l'= min \{l_{a} | a \in A\}, we will regard the voting matrices which make the set {a∈A∣la=l′}\{a \in A | l_{a} = l' \} as admissible. For each such matrix, the single candidate in this set will get elected according to majoritarian compromise. Moreover, if w1≥w2≥...≥wk≥0w_{1} \geq w_{2} \geq ... \geq w_{k} \geq 0 are given, for each admissible voting matrix, ∑i=1kwiai\sum^{k}_{i=1}{w_{i}a_{i}} is called the total weighted score of a∈Aa \in A. We will say that the system (w1,w2,...,wk)(w_{1},w_{2}, . . . , w_{k}) of weights represents majoritarian compromise if the total score of the elected candidate is maximum among the scores of all candidates. (a) Determine whether there is a system of weights representing majoritarian compromise if k=3k = 3. (b) Show that such a system of weights does not exist for k>3k > 3.

    Dataset text AoPS wiki problems. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator tr-mo/1997/p3 · Tag VAT3RBCRHR · Edit this page on GitHub · Keys: j next, k previous