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SIMON-MARAIS 2022 B4

  • Paper B

The following problem is open in the sense that the answer to part (b) is not currently known. A solution to part (a) will be awarded 7 points. Up to 7 additional points may be awarded for progress on part (b).

Let a0,a1,a2,…a_0, a_1, a_2, \ldots and b0,b1,b2,…b_0, b_1, b_2, \ldots be two sequences of positive integers, satisfying a0b0≥600a_0b_0 \geq 600 and

an+1=an+2⋅⌊bn/20⌋,a_{n+1} = a_n + 2 \cdot \lfloor b_n/20 \rfloor,

bn+1=bn+3⋅⌊an/30⌋,b_{n+1} = b_n + 3 \cdot \lfloor a_n/30 \rfloor,

for all n≥0n \geq 0.

(a) Prove that there exists a nonnegative integer NN such that

−13≤an−bn≤23,-13 \leq a_n - b_n \leq 23,

for all n≥Nn \geq N.

(b) Must there exist a nonnegative integer nn such that an=bna_n = b_n?

Here ⌊x⌋\lfloor x \rfloor denotes the greatest integer less than or equal to xx.

Official text Simon Marais Mathematics Competition 2022 official paper, page 2. Quoted with source.

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