olymmath

SHARYGIN 2023 Problem 2

    The diagonals of a rectangle ABCDABCD meet at point EE . A circle centered at EE lies inside the rectangle. Let CFCF , DGDG , AHAH be the tangents to this circle from CC , DD , AA ; let CFCF meet DGDG at point II , EIEI meet ADAD at point JJ , and AHAH meet CFCF at point LL . Prove that LJLJ is perpendicular to ADAD .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator sharygin/2023/p2 · Tag KRNCB7VRF0 · Edit this page on GitHub · Keys: j next, k previous