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SHARYGIN 2018 Problem 14

    Let ABCABC be a right-angled triangle with ∠C=90∘\angle C = 90^{\circ} , KK , LL , MM be the midpoints of sides ABAB , BCBC , CACA respectively, and NN be a point of side ABAB . The line CNCN meets KMKM and KLKL at points PP and QQ respectively. Points SS , TT lying on ACAC and BCBC respectively are such that APQSAPQS and BPQTBPQT are cyclic quadrilaterals. Prove that

    a) if CNCN is a bisector, then CNCN , MLML and STST concur;

    b) if CNCN is an altitude, then STST bisects MLML .

    Dataset text AI-MO AoPS. Quoted with source.

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