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SHARYGIN 2015 Problem 7

    The altitudes AA1AA_1 and CC1CC_1 of a triangle ABCABC meet at point HH. Point HAH_A is symmetric to HH about AA. Line HAC1H_AC_1 meets BCBC at point C′C'; point A′A' is defined similarly. Prove that A′C′∥ACA'C' \parallel AC.

    Official text Sharygin Geometry Olympiad 2015 official paper, page 2. Quoted with source.

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