olymmath

SHARYGIN 2015 Problem 2

    Let OO and HH be the circumcenter and the orthocenter of a triangle ABCABC. The line passing through the midpoint of OHOH and parallel to BCBC meets ABAB and ACAC at points DD and EE. It is known that OO is the incenter of triangle ADEADE. Find the angles of ABCABC.

    Official text Sharygin Geometry Olympiad 2015 official paper, page 2. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/local (GLM-OCR-8bit). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator sharygin/2015/p2 · Tag TH97MPK4A3 · Edit this page on GitHub · Keys: j next, k previous