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SHARYGIN 2014 Problem 8

    Given a rectangle ABCDABCD. Two perpendicular lines pass through point BB. One of them meets segment ADAD at point KK, and the second one meets the extension of side CDCD at point LL. Let FF be the common point of KLKL and ACAC. Prove that BF⊥KLBF \perp KL.

    Official text Sharygin Geometry Olympiad 2014 official paper, page 2. Quoted with source.

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