olymmath

SHARYGIN 2013 Problem 20

    Let C1C_1 be an arbitrary point on the side ABAB of triangle ABCABC . Points A1A_1 and B1B_1 on the rays BCBC and ACAC are such that ∠AC1B1=∠BC1A1=∠ACB\angle AC_1B_1 = \angle BC_1A_1 = \angle ACB . The lines AA1AA_1 and BB1BB_1 meet in point C2C_2 . Prove that all the lines C1C2C_1C_2 have a common point.

    Dataset text AI-MO AoPS. Quoted with source.

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