olymmath

SHARYGIN 2013 Problem 1

    Let ABCABC be an isosceles triangle with AB=BCAB = BC. Point EE lies on the side ABAB, and EDED is the perpendicular from EE to BCBC. It is known that AE=DEAE = DE. Find ∠DAC\angle DAC.

    Official text Sharygin Geometry Olympiad 2013 official paper, page 2. Quoted with source.

    A model read this text from the scan of the paper by OCR, with vision/local (GLM-OCR-8bit). No person has checked it against the paper yet.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator sharygin/2013/p1 · Tag 4KYJ6HH763 · Edit this page on GitHub · Keys: j next, k previous