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SHARYGIN 2012 Problem 1

    In triangle ABCABC point MM is the midpoint of side ABAB, and point DD is the foot of altitude CDCD. Prove that ∠A=2∠B\angle A = 2\angle B if and only if AC=2MDAC = 2MD.

    Official text Sharygin Geometry Olympiad 2012 official paper, page 1. Quoted with source.

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