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SHARYGIN 2010 Problem 7

    The line passing through the vertex BB of a triangle ABCABC and perpendicular to its median BMBM intersects the altitudes dropped from AA and CC (or their extensions) in points KK and NN. Points O1O_1 and O2O_2 are the circumcenters of the triangles ABKABK and CBNCBN respectively. Prove that O1M=O2MO_1M = O_2M.

    Official text Sharygin Geometry Olympiad 2010 official paper, page 2. Quoted with source.

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